Subnetting a class C address in your head

In our example we apply the subnet mask 255.255.255.128 [ /25] to the network 192.16.11.0.

Subtract 25 from 32 total mask bits to leave 7 unmask bits which give way to host bits. Find the total address, including subnet and broadcast, per subnet chunk by raising 2 to the power of unmask bits.

Remember 2^8 = 256

2^7 = (2^8) / 2 = 128

Count from 0 by increments found in your computed answer to 256.

In this case we established two subnets using the /25 netmask.

Subnet     First Host     Last Host     Broadcast

0                 1                      126                 127

128             129                 254                 255